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how much polyfill does it take to simulate .5 Cubic feet?

Discussion in 'Audio' started by RingMaster4x4, Oct 29, 2003.

  1. RingMaster4x4

    RingMaster4x4 1/2 ton status Premium Member

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    The title says it all. /forums/images/graemlins/thinking.gif
     
  2. Greg72

    Greg72 "Might As Well..." Staff Member Super Moderator

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  3. RingMaster4x4

    RingMaster4x4 1/2 ton status Premium Member

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    Ok thanks for the link Greg. I will check it out.
     
  4. RingMaster4x4

    RingMaster4x4 1/2 ton status Premium Member

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    I looked at it and I am confused. I have a box that is 2.45 CF per chamber. The driver has a Displacement - 432 cu in. There needs to be atleast 2.50 CF per chamber.. is there a formula or some thing I can use? Math is not one of my strong points. /forums/images/graemlins/thinking.gif
     
  5. Greg72

    Greg72 "Might As Well..." Staff Member Super Moderator

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    [ QUOTE ]
    I looked at it and I am confused. I have a box that is 2.45 CF per chamber. The driver has a Displacement - 432 cu in. There needs to be atleast 2.50 CF per chamber.. is there a formula or some thing I can use? Math is not one of my strong points. /forums/images/graemlins/thinking.gif

    [/ QUOTE ]


    Here are the basics:

    2.45 CuFt = 4233 cu in
    Driver Displacment = 432 cu in
    Total Volume = 4233 - 432 (3801 cu in) which equal 2.2 Cu ft

    Using the rule of thumb suggested, you can gain 30% more effective volume by stuffing with 1.5 Lbs/cu ft of enclosure volume....That would give you:

    2.2 Cu Ft * .30 = .66 cu ft extra volume = 2.86 Cu Ft per side.


    SO....you need to stuff 3.3 Lbs of polyfill into each side to get to that 2.86 Cu Ft volume.



    /forums/images/graemlins/thumb.gif
     
  6. RingMaster4x4

    RingMaster4x4 1/2 ton status Premium Member

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    you da man greg!! /forums/images/graemlins/thumb.gif /forums/images/graemlins/thumb.gif Thanks for you knowledge once again.
     

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