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Need help with a calculation

Discussion in 'The Lounge' started by sled_dog, Feb 23, 2004.

  1. sled_dog

    sled_dog 1 ton status

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    Alright I located my rear under the buggy and I want to figure out what angle my lower links are at. I did some math and found that from the axle end of the link to the frame mount is a 1" rise. This takes place over 31.5". So can I take those numbers and figure out the angle of them? I asked my dad the master carpenter and he didn't freaking know /forums/images/graemlins/rotfl.gif said he always uses a "345" square so doesn't have to know it.
     
  2. wraenking

    wraenking 1/2 ton status

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    i dont know if that will give you and angle. it will more give you a slope percentage.

    %slope vdx x 100
    _________
    HD


    vd = verdical difference

    HD is your distance.

    wait for an expert to reply though
     
  3. Resurrection_Joe

    Resurrection_Joe 1 ton status

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    Yeah you can do it, I forget how though, simple trig

    Your links rise and inch over 31.5"? I have no idea, but that doesn't sound right, maybe I'm just too ignorant of linked suspension

    Damn it..... trying to remeber triginometry

    Uh, from my ass math, I think 1.8*

    31.5" as the radius of a circle

    63" Diameter

    197.82" Circumference

    49.455" Through 90*

    1.82* for every inch of travel through the 90*

    Orrr uhhh yeahhhh

    I realize this method gets way more off as the inch in question gets bigger, but I figure it's around 2*
     
  4. sled_dog

    sled_dog 1 ton status

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    probably more like 18*. What doesn't sound right about it? The goal is the lower link as close to parrellel with the ground as I can get it.
     
  5. 84k5

    84k5 1/2 ton status

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    (sin) old hippies (cos) are high (tan) on acid

    sin (theta) = opposite/hypotenuse
    cos (theta) = adjacent/hypotenuse
    tan (theta) = opposite/adjacent

    Fell asleep in the sixth grade huh? /forums/images/graemlins/whistling.gif
     
  6. Resurrection_Joe

    Resurrection_Joe 1 ton status

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    Like I said dude, I have NOOOOO idea about linked suspensions, if the links are supposed to be flat as possible, I'll go with that
     
  7. sled_dog

    sled_dog 1 ton status

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    shut my mind off a few years ago. Been too long since Geometry.
     
  8. Stickseler

    Stickseler 3/4 ton status

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    1.82 DEG or 88.18 DEG off level

    Tell your dad to buy a Construction Master Pro /forums/images/graemlins/tongue.gif
     
  9. 84k5

    84k5 1/2 ton status

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    Joe's got it right, that's just the hard way. Use the inverse tangent function on 1/31.5
     
  10. sled_dog

    sled_dog 1 ton status

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    I'm no genius of this stuff, guys around here know a lot more than me. I just tried to get a little angle on the lower links, 10" distance between the upper and lowers, and half that at the other end. 45* angle on the upper links to control side to side.
     
  11. Resurrection_Joe

    Resurrection_Joe 1 ton status

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    I WIN I WIN I WIN

    This is like the time I went on a field trip to the dam in Pierre SD. I identified thier air compressors as old WW2 airplane engines, and I felt smart, but no prize, I said "Where's my dam prize?", get it? They didn't have a souvenier shop......
     
  12. justinf

    justinf 1/2 ton status

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    You are looking for the angle relative to the ground correct? If so, take the inverse sine of (1/31.5). Which gives you an angle of 1.82 degrees.
     
  13. sled_dog

    sled_dog 1 ton status

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    inverse tangent, inverse sine, which is it?
     
  14. sled_dog

    sled_dog 1 ton status

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    ok 1/31.5(sin) and (tangent) both work out to 5.5*.
     
  15. 84k5

    84k5 1/2 ton status

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    Tangent. It would be sine if the link was 31.5" long, not the distance parallel to the ground. The answer is almost the same because the angle is so small.
     
  16. sled_dog

    sled_dog 1 ton status

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    [​IMG]
    hmm looking at the pictures it does look more like 1.8*. My back is up against the fence of my dogs cage so I can't look any better.
     
  17. 84k5

    84k5 1/2 ton status

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    Inverse tangent. It is 1.818302964
     
  18. justinf

    justinf 1/2 ton status

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    You're right, I looked at it and figured 31.5" was the length of the link. When you plug it in, it should give you 1.82 degrees, not 5.5 degrees. Like 84k5 said, with such a small rise over that distance, it doesn't affect it very much.
     
  19. sled_dog

    sled_dog 1 ton status

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    inverse tangent, hmmm how do I do that?
     
  20. justinf

    justinf 1/2 ton status

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    Look at your calculator, most scientific ones have a shift key with additional functions listed above the keys. Usually, inverse tangent is listed above the tangent key. and is labelled tangent raised to the minus one power. (tan-1)
     

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