BDS 6\" spring rate.....is this right?? **UPDATED** I am using this formula provided by Greg72 (Thanks): Leaf Spring Rate=(WN/12) x (1000T/L)^3 W=width of leaves N=number of leavbes in the pack (minus overload) T=total thickness of pack (minus overload)/total # of leaves L=length of spring eye-to-eye 12=constant for leaf spring Here are my calculations: W=2.5 N=5 T=.4 L=45.5 After putting my numbers into this equation I get a whopping number of 707.741 /forums/images/graemlins/shocked.gif I then called ORD to see what the ideal spring rate is for a K5 and they said 250-300. I haven't been able to confirm if my number is right because BDS's contact info is down on their website. The reason I calculated my spring rate was because of the ride was so rough. I m thinking about taking the overload spring off the bottom of the spring pack and seeing if that makes it ride any better.