Sorry, not to be an ass, but it's not an opinion, it's physics. Voltage does drop along a length of wire, it's a resistor that varies based on cross section area and length. The smaller the wire, or longer the run, the more the drop. This drop results in loss through heat (which is why small wires burn up easier). It's a simple fact that the lights *can not* see full voltage after routing from source, to the dash, through the switch, and back to the lights. That voltage drop means the lights can not produce their rated wattage due to W = VA. Lower V than rated means lower W, which is lower light output. Shorter runs of heavier wire result in less drop so you can at least approach the rated (legal limit) output of the lights.
As for the “all on” mod; try to push too many amps across the wire (particularly in a bundle) and you melt the insulation. Likewise, the switch can only handle so much amperage before doing a melt down. In the normal case you have roughly 4.5 amps per bulb on low beam, and 5.4 amps per bulb on high. That comes to 9.16 amps total for low beam circuit and 10.83 amps for the high. So the "all on" mod pulls 20A across the power wire to the switch and through the switch, basically doubling the factory load. It also pulls 20A through the high beam wire alone on it's way to the relay. Check the wire gauge load limits and you'll see that the factory harness is right on it's limit there, and that limit is based on open air runs, not "in a bundle" and wrapped in a harness loom/tape.
[Note: For the engineers out there I am actively ignoring cumulative and parasitic effects for simplicity.]
Check out
this page for a handy calculator and table that indicates amperage ratings for wire size and voltage drops based on wire size, run length, etc. I found this on Google, but there are others.