I think what a lot of people expect is for the alarm to use a bunch of current in the arm state. I would not expect it to use much more current armed then disarmed with the primary source of current draw being the LED light that blinks when armed. An LED light that blinks is actually probably to fast and to low of a current for the multimeter to catch since it will be RMS current. So minor changes won't show up when the major source of current is comming from somewhere else.What it proves is the alarm is on and that it is drawing less then 60 mA. How much it does it really need to monitor a closed door switch?
What else it proves is that since it is hard wire to constant power is that it draws NO more electricity when armed then when unarmed. It has the same draw both armed and unarmed. So while Jim THINKS it could not be armed because it wasn't a high enough draw for his liking, it was in fact ON and ARMED.
About the best think you could do would be to measure the current draw with the alarm power wire disconnected. Then measure the current throught the power wire of the alarm. Add to two tegether and you will get the total current which should be around 60mA.
Your kinda beating a dead horse here as you already know the source of the problem but if you feel like doing it that is what I would do.





