OK, made it back.
If you have the speed and room you might want to download this .PDF file.
http://www.carlingtech.com/sites/default/files/documents/Carling-RS-V-Series_0.pdf
You can view it online, but it takes a while to move between the pages online.
Pages 8 and 9 are the ones to see.
The switch version you linked to was this one.
V2D2GHNB-AAC00-000
The second position of the part number refers to the internal circuit, which is page 8.
The fifth position is the lighting circuit which is page 9.
In this part number, the internal circuit is number 2, and the lighting circuit is a G.
Looking at circuit 2, the little triangle means its momentary. When you press the button, it connects pin 2 to pin 3 as long as you hold it. As far as this part is concerned, it would not matter which wires went to which pins.
Where it becomes critical, is in the circuit on page 9. That switch uses circuit G/7. Actually, it uses circuit G, but some switches use the same circuit, but its called 7.
In that circuit, the lighting LED, is number 1. Its powered by the dash light circuit attached to pin 8.
Ground is pin 7.
The "switch on" LED uses the same ground pin 7, and is hooked to pin 3. It gets its power from contact 2 when you press the button and hook pin 2 to pin 3.
With this switch, if you hooked power to pin 3 and the load to pin 2, the switch would work, but the LED would stay on all the time.
But, that is not your problem. Your problem is, that the switch is designed to work with positive voltage.
You are switching ground, which is negative.
In this case, you hook positive voltage to pin 8 which powers the illumination LED through a ground hookup on pin 7.
But then, you hook a ground to pin 2 which is hooked to nothing until you press the button.
Pin 3, is hooked to a hot load, such as the interior lights. The other end of the "power on" LED is always hooked to ground through pin 7.
So, the current from the hot load goes through the LED to ground and causes it to light.
When you press the button, you ground pin 3, which causes that LED to have ground on both ends.
No current flows, and the light goes out.
Let me know if that makes sense. Follow the circuits on the two pages. Circuit 2 and circuit G are actually the two halves of the same switch. If you print one of them out, you could draw in the other half if that would help.
There is probably a switch configuration that would work, I'll look. But that would mean ordering a different switch.
It would be a lot easier to simply add a cheap relay to do the actual ground switching, wire the switch the way its designed to be wired, and let it turn the relay on and off.