Just last year i watch a friend in a K5 truggy get stuck in a mud hole with only his front axle and they broke 2 30K straps trying to get him out and then had to change direction as how to extract him.
So lets see what it took for said vehicle.
Truggy weighs 5,000 pounds
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[FONT=Arial, Arial, Helvetica]Stuck (mire) resistance:
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A pull of 200% of LW will be required if the truck is stuck to the hubs.[/FONT][/FONT][/FONT]
So that would be 15,000 pounds
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[FONT=Arial, Arial, Helvetica]Surface resistance
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A pull of 1/3 LW will cause a free wheeling truck to move on a softer surface, such as grass or gravel,[/FONT][/FONT][/FONT]
So that would be 20,000 pounds
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[FONT=Arial, Arial, Helvetica]Grade (slope) resistance:
[FONT=Arial, Arial, Helvetica]Upgrade (vehicle has to be recovered up a slope or grade) [/FONT][FONT=Arial, Arial, Helvetica]
15 degrees - add 25% of LW
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So that would be 25,000 pounds
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[FONT=Arial, Arial, Helvetica]Final figure:
[FONT=Arial, Arial, Helvetica]Add surface or damage or mire resistance and grade resistance, and this is your final figure or rolling resistance. This is the amount of pull the winch must apply in order to recover the stuck vehicle.[/FONT][FONT=Arial, Arial, Helvetica]
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If I understand it and did the math right (I sux at math) It should of taken almost 25,000 pounds force to free.
Sounds like he might of been more like 300% on the mire being he was axle deep