okay, that makes sense and I can see that (the lightbulbs are slowly getting lit, I am old so they are incandescent instead of LED)
So the engine inputs the RPM at 2536RPM to the transmission input shaft.
The transmission ratio is 0.69 which means the input shaft turns 0.69 times to every one revolution of the output shaft, which is turning at 3675rpm Since the transfer case is in high range which is 1:1, the input and output speeds are still 3675rpm which is also the speed of the driveshaft and the pinion.
The pinion then spins 5.13 times per every revolution of the axle shaft, dropping the axle shaft speed to 716 RPM.
same reply. thank you; like I said, it is starting to make sense. so my formula I found is actually for axle shaft instead of pinion?