Fellas, I need some mathematical help concerning the effects favoring inertia in regards to weight v/s diameter on different flywheels that I have.
Please speak in basic lingo as I am more grease monkey than intellect - after all it took me three years to get a two year degree thirty-five plus years ago ( apparently you’re supposed to show up to all the classes on a regular basis….).
I need to get an idea of how effective each flywheel is compared to each other - as in assigning a numerical value to the inertia/kinetic energy of the mass of each type.
I am working with a 168 tooth 14” overall diameter flywheel that is NOT scalloped on the back side and weighs in at 54lbs. ( compared to 37lbs. for a normal truck type flywheel that is scalloped on the back side ) - this came off of a counter rotating marine 454 that I got years ago and had balanced.
After a lot of thought on how happy I was to have a genuinely heavy flywheel for helping out on low end grunt I decided to get a larger flywheel ( and related parts ) from a C-60 Top-Kick 427-TD that is a 197 tooth and 17.5” diameter but it only weighs in at 47lbs.
I am hoping that the larger diameter, yet lesser weight, of the 197 tooth flywheel , compared to the ultra heavy 168 tooth flywheel , will have a greater inertia effect but I need to measure this somehow.
I’m getting lost in the equations trying to assign a value to what I am seeking and understanding a comparison between just how effective one is compared to the other ( RADIUS 1/2 MR^2 ) is all that I have come up with but I still don’t understand what the equation gives me???
Is it a measure of moment of movement or some description of kinetic energy that resists changes - please help if ya can; I need some basic talk understanding so I can see how effective the larger flywheel is over the smaller, yet heavier, flywheel.
Pics are below for reference - the bottom two pics are the flywheels in question.
Thanks, Tom




Please speak in basic lingo as I am more grease monkey than intellect - after all it took me three years to get a two year degree thirty-five plus years ago ( apparently you’re supposed to show up to all the classes on a regular basis….).
I need to get an idea of how effective each flywheel is compared to each other - as in assigning a numerical value to the inertia/kinetic energy of the mass of each type.
I am working with a 168 tooth 14” overall diameter flywheel that is NOT scalloped on the back side and weighs in at 54lbs. ( compared to 37lbs. for a normal truck type flywheel that is scalloped on the back side ) - this came off of a counter rotating marine 454 that I got years ago and had balanced.
After a lot of thought on how happy I was to have a genuinely heavy flywheel for helping out on low end grunt I decided to get a larger flywheel ( and related parts ) from a C-60 Top-Kick 427-TD that is a 197 tooth and 17.5” diameter but it only weighs in at 47lbs.
I am hoping that the larger diameter, yet lesser weight, of the 197 tooth flywheel , compared to the ultra heavy 168 tooth flywheel , will have a greater inertia effect but I need to measure this somehow.
I’m getting lost in the equations trying to assign a value to what I am seeking and understanding a comparison between just how effective one is compared to the other ( RADIUS 1/2 MR^2 ) is all that I have come up with but I still don’t understand what the equation gives me???
Is it a measure of moment of movement or some description of kinetic energy that resists changes - please help if ya can; I need some basic talk understanding so I can see how effective the larger flywheel is over the smaller, yet heavier, flywheel.
Pics are below for reference - the bottom two pics are the flywheels in question.
Thanks, Tom
